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  • Vendor : VMware
  • Certifications : VCAP-CMA Design 2021
  • Exam Name : Advanced Design VMware Cloud Management and Automation
  • Exam Code : 3V0-32.21
  • Total Questions : 376 Q&As
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What is VCE Simulator?
VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.
SKU: 3V0-32.21 Categories: ,

Description

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    NEW QUESTION: 1
    Which component should you use to display a series of meetings in a Portal?
    A. Calendar
    B. Events - Mini View
    C. Personal Events
    D. Announcements
    Answer: B
    Explanation:
    Reference:
    http://docs.oracle.com/cd/E29542_01/doc.1111/e27603/servtool_cal_evnt.htm

    NEW QUESTION: 2
    Your database contains tables named Products and ProductsPriceLog. The Products table contains columns named ProductCode and Price. The ProductsPriceLog table contains columns named ProductCode, OldPrice, and NewPrice. The ProductsPriceLog table stores the previous price in the OldPrice column and the new price in the NewPrice column. You need to increase the values in the Price column of all products in the Products table by 5 percent. You also need to log the changes to the ProductsPriceLog table. Which Transact-SQL query should you use?
    A. UPDATE Products SET Price = Price * 1.05
    OUTPUT inserted.ProductCode, deleted.Price, inserted.Price
    INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
    B. UPDATE Products SET Price = Price * 1.05
    OUTPUT inserted.ProductCode, deleted.Price, inserted.Price *
    INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
    C. UPDATE Products SET Price = Price * 1.05 INSERT INTO ProductsPriceLog (ProductCode, CldPnce, NewPrice; SELECT ProductCode, Price, Price * 1.05 FROM Products
    D. UPDATE Products SET Price = Price * 1.05
    OUTPUT inserted.ProductCode, inserted.Price, deleted.Price
    INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
    Answer: A
    Explanation:
    Reference: http://msdn.microsoft.com/en-us/library/ms177564.aspx

    NEW QUESTION: 3
    Which type of EIGRP routes are summarized by the auto-summary command?
    A. external routes that are learned from a peer that is inside the range of local network statements
    B. external routes that are learned from a peer that is outside the range of local network statements
    C. internal routes that are learned from a peer that is outside the range of local network statements
    D. locally created routes that are outside the range of local network statements
    Answer: A
    Explanation:
    Auto-Summarization of External Routes
    EIGRP will not auto-summarize external routes unless there is a component of the same major network that is an internal route. To illustrate, let us look at Figure 15.

    Router Three is injecting external routes to 192.1.2.0/26 and 192.1.2.64/26 into EIGRP using the
    redistribute connected command, as shown in the configurations below.
    Router Three
    interface Ethernet0 ip address 192.1.2.1 255.255.255.192 ! interface Ethernet1 ip address 192.1.2.65 255.255.255.192 ! interface Ethernet2 ip address 10.1.2.1 255.255.255.0 !router eigrp 2000 redistribute connected network 10.0.0.0 default-metric 10000 1 255 1 1500 With this configuration on Router Three, the routing table on Router One shows: one# show ip route 10.0.0.0/8 is subnetted, 2 subnets D 10.1.2.0 [90/11023872] via 10.1.50.2, 00:02:03, Serial0 C 10.1.50.0 is directly connected, Serial0 192.1.2.0/26 is subnetted, 1 subnets D EX 192.1.2.0 [170/11049472] via 10.1.50.2, 00:00:53, Serial0 D EX 192.1.2.64 [170/11049472] via 10.1.50.2, 00:00:53, Serial0 Although auto-summary normally causes Router Three to summarize the 192.1.2.0/26 and 192.1.2.64/26 routes into one major net destination (192.1.2.0/24), it does not do this because both routes are external. However, if you reconfigure the link between Routers Two and Three to 192.1.2.128/26, and add network statements for this network on Routers Two and Three, the 192.1.2.0/24 auto-summary is then generated on Router Two.
    Router Three
    interface Ethernet0 ip address 192.1.2.1 255.255.255.192 ! interface Ethernet1 ip address 192.1.2.65 255.255.255.192 ! interface Serial0 ip address 192.1.2.130 255.255.255.192 ! router eigrp 2000 network 192.1.2.0 Now Router Two generates the summary for 192.1.2.0/24: two# show ip route
    D 192.1.2.0/24 is a summary, 00:06:48, Null0
    And Router One shows only the summary routE. one# show ip route
    10.0.0.0/8 is subnetted, 1 subnets C 10.1.1.0 is directly connected, Serial0 D 192.1.2.0/24 [90/11023872] via 10.1.50.2, 00:00:36, Serial0
    Reference: http://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routingprotocol-eigrp/16406-eigrp-toc.html

    NEW QUESTION: 4



    A. Option A
    B. Option B
    C. Option D
    D. Option E
    E. Option C
    Answer: A,E
    Explanation:
    The loading sequence of CISCO IOS is as follows: Booting up the router and locating the Cisco IOS
    1.POST (power on self-test)
    2.Bootstrap code executed
    3.Check Configuration Register value (NVRAM) which can be modified using the configregister command
    0 = ROM Monitor mode 1 = ROM IOS 2 - 15 = startup-config in NVRAM
    4.Startup-config filE. Check for boot system commands (NVRAM)
    If boot system commands in startup-config
    a.Run boot system commands in order they appear in startup-config to locate the IOS
    b.[If boot system commands fail, use default fallback sequence to locate the IOS (Flash,
    TFTP, ROM)?]
    If no boot system commands in startup-config use the default fallback sequence in locating
    the IOS:
    a.Flash (sequential)
    b.TFTP server (netboot)
    c.ROM (partial IOS) or keep retrying TFTP depending upon router model
    5. If IOS is loaded, but there is no startup-config file, the router will use the default fallback
    sequence for locating the IOS and then it will enter setup mode or the setup dialogue.


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