Practice Test CLA-11-03 Fee | CLA-11-03 Exam Fee & CLA-11-03 Accurate Prep Material - Championlandzone

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  • Vendor : C++ Institute
  • Certifications : C++ Institute Certification
  • Exam Name : CLA - C Certified Associate Programmer
  • Exam Code : CLA-11-03
  • Total Questions : 376 Q&As
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What is VCE Simulator?
VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.


What is VCE Simulator?
VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.
SKU: CLA-11-03 Categories: ,

Description

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    NEW QUESTION: 1
    Note: This question is part of a series of questions that use the same or similar answer choices.
    An answer choice may be correct for more than one question in the series.
    Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
    You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

    You need to run a query to find the total number of customers who have both deposit and loan accounts.
    Which Transact-SQL statement should you run?
    A. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
    B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
    C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
    D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
    E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
    F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
    G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
    H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
    Answer: H
    Explanation:
    The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
    References: https://www.techonthenet.com/sql/intersect.php

    NEW QUESTION: 2

    A. Option D
    B. Option C
    C. Option B
    D. Option A
    Answer: C

    NEW QUESTION: 3
    A technician wants to prevent an unauthorized host from connecting to the network via Ethernet. Which of
    the following is a Layer 2 access control the technician should implement?
    A. Captive portal
    B. WPA2
    C. Access control lists
    D. Port security
    Answer: D


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