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NEW QUESTION: 1
Which of the following vulnerabilities can lead to unexpected system behavior, including the bypassing of security controls, due to differences between the time of commitment and the time of execution?
A. Pointer dereference
B. Race condition
C. DLL injection
D. Buffer overflow
Answer: D
Explanation:
Explanation
Buffer overflow protection is any of various techniques used during software development to enhance the security of executable programs by detecting buffer overflows on stack-allocated variables, and preventing them from causing program misbehavior or from becoming serious security vulnerabilities.
DLL injection is a technique which allows an attacker to run arbitrary code in the context of the address space of another process. If this process is running with excessive privileges then it could be abused by an attacker in order to execute malicious code in the form of a DLL file in order to elevate privileges.

NEW QUESTION: 2
You have three servers located in a DMZ, using private IP addresses. You want internal users from 10.10.10.x to access the DMZ servers by public IP addresses. Internal_net
10.10.10.x is configured for Hide NAT behind the Security Gateway's external interface.

What is the best configuration for 10.10.10.x users to access the DMZ servers, using the DMZ servers' public IP addresses?
A. When connecting to the Internet, configure manual Static NAT rules to translate the DMZ servers.
B. When the source is the internal network 10.10.10.x, configure manual static NAT rules to translate the DMZ servers.
C. When connecting to internal network 10.10.10.x, configure Hide NAT for the DMZ network behind the Security Gateway DMZ interface.
D. When trying to access DMZ servers, configure Hide NAT for 10.10.10.x behind the DMZ's interface.
Answer: B

NEW QUESTION: 3
Given:

Which statement is equivalent to line 1?
A. double totalSalary = list.stream().map(Employee::getSalary * ratio).reduce (bo).orElse(0.0);
B. double totalSalary = list.stream().mapToDouble(e > e.getSalary() * ratio).reduce(starts, bo);
C. double totalSalary = list.stream().map(e > e.getSalary() * ratio).reduce (bo).ifPresent (p > p.doubleValue());
D. double totalSalary = list.stream().mapToDouble(e > e.getSalary() * ratio).sum;
Answer: A
Explanation:

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