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NEW QUESTION: 1
注：この質問は、同じシナリオを提示する一連の質問の一部です。シリーズの各質問には、指定された目標を達成する可能性のある独自のソリューションが含まれています。一部の質問セットには複数の正しい解決策がある場合がありますが、他の質問セットには正しい解決策がない場合があります。
このセクションの質問に回答した後は、その質問に戻ることはできません。その結果、これらの質問はレビュー画面に表示されません。
会社にオンプレミスデータセンターとAzureサブスクリプションがあります。オンプレミスのデータセンターには、ハードウェアセキュリティモジュール（HSM）が含まれています。
ネットワークに、Azure Active Directory（Azure AD）テナントと同期されているActive Directoryドメインが含まれています。
同社はApplication1というアプリケーションを開発しています。 Application1は、次を使用してAzureでホストされます
Windows Server 2016を実行する10台の仮想マシン。5台の仮想マシンは西ヨーロッパのAzureリージョンにあり、5台の仮想マシンは米国東部のAzureリージョンにあります。仮想マシンは、会社の機密情報を保存します。すべての仮想マシンは管理対象ディスクを使用します。
BitLockerドライブ暗号化（BitLocker）を使用して仮想マシンディスクを暗号化するソリューションを推奨する必要があります。
ソリューション：各リージョンに1つのAzure Key Vaultをデプロイします。 Azure Disk Encryptionを使用するように仮想マシンを構成します。各リージョンの仮想マシンディスクを暗号化するには、異なるKey Vaultを使用します。
これは目標を達成していますか？
A. はい
B. いいえ
Answer: B
Explanation:
The security key from the on-premises HSM need to be exported.
Reference:
https://docs.microsoft.com/en-us/azure/security/azure-security-disk-encryption-prerequisites-aad

NEW QUESTION: 2
View the Exhibit.

You are designing an IP addressing scheme for the network in the exhibit above.
Each switch represents hosts that reside in separate VLANs. The subnets should be allocated to match the following host capacities:
Router subnet: two hosts

SwitchA subnet: four hosts

SwitchB subnet: 10 hosts

SwitchC subnet: 20 hosts

SwitchD subnet: 50 hosts

You have chosen to subnet the 192.168.51.0/24 network.
Which of the following are you least likely to allocate?
A. a /26 subnet
B. a /28 subnet
C. a /25 subnet
D. a /27 subnet
E. a /29 subnet
F. a /30 subnet
Answer: C
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
Of the available choices, you are least likely to allocate a /25 subnet. The largest broadcast domain in this scenario contains 50 hosts. A /25 subnet can contain up to 126 assignable hosts. In this scenario, allocating a /25 subnet would reserve half the 192.168.51.0/24 network for a single virtual LAN (VLAN).
The total number of hosts for which you need addresses in this scenario is 86. Therefore, you would only need to use half the /24 subnet if all 86 hosts were residing in the same VLAN.
You should begin allocating address ranges starting with the largest group of hosts to ensure that the entire group has a large, contiguous address range available. Subnetting a contiguous address range in structured, hierarchical fashion enables routers to maintain smaller routing tables and eases administrative burden when troubleshooting.
You are likely to use a /26 subnet. In this scenario, the largest VLAN contains 50 hosts. If you were to divide the 192.168.51.0/25 subnet into two /26 subnets, the result would be two new subnets capable of supporting up to 62 assignable hosts: the 192.168.51.0/26 subnet and the 192.168.51.64/26 subnet.
Therefore, you should start subnetting with a /26 network. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.64/26 subnet to SwitchD's VLAN.
You are likely to use a /27 subnet. The nextlargest broadcast domain in this scenario is the SwitchC subnet, which contains 20 hosts. If you were to divide the 192.168.51.0/26 subnet into two /27 subnets, the result would be two new subnets capable of supporting up to 30 assignable hosts: the 192.168.51.0/27 subnet and the 192.168.51.32/27 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.32/27 subnet to SwitchC's VLAN.
You are likely to use a /28 subnet. The nextlargest broadcast domain in this scenario is the SwitchB subnet, which contains 10 hosts. If you were to divide the 192.168.51.0/27 subnet into two /28 subnets, the result would be two new subnets capable of supporting up to 14 assignable hosts: the 192.168.51.0/28 subnet and the 192.168.51.16/28 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.16/28 subnet to SwitchB's VLAN.
You are likely to use a /29 subnet. The nextlargest broadcast domain in this scenario is the SwitchA subnet, which contains four hosts. If you were to divide the 192.168.51.0/28 subnet into two /29 subnets, the result would be two new subnets capable of supporting up to six assignable hosts: the 192.168.51.0/29 subnet and the 192.168.51.8 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.8/29 subnet to SwitchA's VLAN.
You are likely to use a /30 subnet. The final subnet in this scenario is the link between RouterA and RouterB, which contains two hosts. If you were to divide the 192.168.51.0/29 subnet into two /30 subnets, the result would be two new subnets capable of supporting two assignable hosts each: the
192.168.51.0/30 subnet and the 192.168.51.4/30 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.4/30 subnet to the link between RouterA and RouterB. This would leave the 192.168.51.0/30 subnet unallocated. However, you could further divide the 192.168.51.0/30 subnet into single /32 host addresses that could then be used for loopback IP addressing on the routers.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 8, IPv4 Address Subnets, pp. 302-310 CCDA 200-310 Official Cert Guide, Chapter 8, Plan for a Hierarchical IP Address Network, pp. 311-312 Cisco: IP Addressing and Subnetting for New Users

NEW QUESTION: 3
In the precedence diagramming method, which of the following is a logical relationship for the activities?
A. Applying leads and lags
B. Finish-to-start
C. Activity-on-node
D. Dependency determination
Answer: B

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