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NEW QUESTION: 1
Your company has an Azure Container Registry named Registry1.
You have an Azure virtual machine named Server1 that runs Windows Server 2019.
From Server1, you create a container image named image1.
You need to add image1 to Registry1.
Which command should you run on Server1? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

An Azure container registry stores and manages private Docker container images, similar to the way Docker Hub stores public Docker images. You can use the Docker command-line interface (Docker CLI) for login, push, pull, and other operations on your container registry.
Reference:
https://docs.microsoft.com/en-us/azure/container-registry/container-registry-get-started-docker-cli
https://docs.docker.com/engine/reference/commandline/push/

NEW QUESTION: 2
Microsoft ExchangeOnlineテナントがあります。
すべてのユーザーには、Office 365 EnterpriseE3ライセンスのみが割り当てられます。
ユーザーがAndroidデバイスから接続するときに、MicrosoftOutlookのみを使用してMicrosoft365メールボックスに接続できるようにする必要があります。
何を作成する必要がありますか？
A. an app protection policy in Microsoft Endpoint Manager
B. a connection filter policy in Exchange Online Protection (EOP)
C. a conditional access policy in Azure Active Directory (Azure AD)
D. an Outlook Web App policy in Exchange Online
Answer: C
Explanation:
Explanation
Office 365 Enterprise E3 includes Azure Active Directory Premium P1 which is required for Azure conditional access policies.

NEW QUESTION: 3
Which of the following is true about aggregation framework?
A. A single aggregation framework operator can be used more than once in a query
B. Each aggregation operator need to return atleast one of more documents as a result
C. Pipeline expressions are stateless except accumulator expressions used with $group operator
D. the aggregate command operates on a multiple collection
Answer: A,B,C

NEW QUESTION: 4
Assuming that the following piece of code has been executed successfully, which of the expressions evaluate to True? (Select two answers)

A. B.VarA == 3
B. obj_b.prop_a == 3
C. hasattr(obj_b, 'prop_aa')
D. isinstance(obj_c,A)
Answer: C,D