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NEW QUESTION: 1
Refer to the exhibit.

Which command provides this output?
A. show ip route
B. show cdp neighbor
C. show ip interface
D. show interface
Answer: B

NEW QUESTION: 2
John works as a project manager of the NHQ Project. He has created the project network diagram as shown in the figure:

Based on the project network diagram, how much float is available for Activity H if Activity B is delayed by four days and Activity E is delayed by two days?
A. Zero
B. One
C. Five
D. Four
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The path of ABEHJ will take 22 days to complete and cannot exceed 28 days or else the project will be late. If Activity B takes four additional days and Activity E takes two additional days, this adds (4+2= 6) six days to the path, bringing the path's duration to exactly (22+6 = 28) days. There is no available float left for Activity D or H. Float or total float (TF) is the total amount of time that a schedule activity may be delayed from its early start date without delaying the project finish date, or violating a schedule constraint. It is calculated by using the critical path method technique and determining the difference between the early finish dates and late finish dates.
Incorrect Answers:
B, C, D: There is no float available because the path's duration has increased to 28 days.

NEW QUESTION: 3

A. Option D
B. Option B
C. Option C
D. Option A
Answer: B,D
Explanation:
Explanation
References:
https://technet.microsoft.com/en-us/library/aa618539.aspx

NEW QUESTION: 4
You are evaluating a method that calculates loan interest. The application includes the following code segment. (Line numbers are included for reference only.)

When the loanTerm value is 5 and the loanAmount value is 4500, the loanRate must be set to 6.5 percent.
You need to adjust the loanRate value to meet the requirements.
What should you do?
A. Replace line 07 with the following code segment: loanRate = 0.065m;
B. Replace line 04 with the following code segment: decimal loanRate = 0.065m;
C. Replace line 17 with the following code segment: interestAmount = loanAmount * 0.065m * loanTerm;
D. Replace line 15 with the following code segment: loanRate = 0.065m;
Answer: D