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  • Exam Code: CTFL_Syll2018-KR
  • Exam Name: ISTQB Certified Tester Foundation Level (Syllabus 2018) (CTFL_Syll2018 Korean Version)
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  • Exam Code: CTFL_Syll2018-KR
  • Exam Name: ISTQB Certified Tester Foundation Level (Syllabus 2018) (CTFL_Syll2018 Korean Version)
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NEW QUESTION: 1
How is the tailoring approach defined for a project?
A. The project board approves the approach
B. Project assurance approves the approach
C. The project board documents the approach
D. Project assurance documents the approach
Answer: A

NEW QUESTION: 2
Which of the following is the unique identifier within and IPSec packet that enables the sending host to reference the security parameter to apply?
A. AH
B. SPI
C. ESP
D. SA
Answer: B
Explanation:
Explanation/Reference:
The Security Parameter Index (SPI) is the unique identifier that enables the sending host to reference the security parameter to apply in order to decrypt the packet.
For you exam you should know the information below about the IPSec protocol:
The IP network layer packet security protocol establishes VPNs via transport and tunnel mode encryption methods.
For the transport method, the data portion of each packet is encrypted, encryption within IPSEC is referred to as the encapsulation security payload (ESP), it is ESP that provides confidentiality over the process.
In the tunnel mode, the ESP payload and its header's are encrypted. To achieve non-repudiation, an additional authentication header (AH) is applied.
In establishing IPSec sessions in either mode, Security Associations (SAs) are established. SAs defines which security parameters should be applied between communicating parties as encryption algorithms, key initialization vector, life span of keys, etc. Within either ESP or AH header, respectively. An SAs is established when a 32-bit security parameter index (SPI) field is defined within the sending host. The SPI is unique identifier that enables the sending host to reference the security parameter to apply, as specified, on the receiving host.
IPSec can be made more secure by using asymmetric encryption through the use of Internet Security Association and Key Management Protocol/Oakley (ISAKMP/Oakley), which allows automated key management, use of public keys, negotiation, establishment, modification and deletion of SAs and attributes. For authentication, the sender uses digital certificates. The connection is made secure by supporting the generation, authentication, distribution of the SAs and the cryptographic keys.
The following were incorrect answers:
SA - Security Association (SA) defines which security parameters should be applied between communicating parties as encryption algorithms, key initialization vector, life span of keys, etc.
ESP - Encapsulation Security Payload (ESP) is used to support authentication of sender and encryption of data
AH - Authentication Header allows authentication of a sender of a data.
The following reference(s) were/was used to create this question:
CISA review manual 2014 Page number353

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct L WHERE D.CustNo = L.CustNo
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
Answer: H
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 4

A. Option D
B. Option B
C. Option A
D. Option C
Answer: A
Explanation:
Reference:
http://www.cisco.com/en/US/docs/security/asa/asa82/configuration/guide/objectgroups.html Explanation:
Information About Object Groups
By grouping like objects together, you can use the object group in an ACE instead of having to enter an ACE for each object separately. You can create the following types of object groups:
*Protocol
*Network
*Service
*ICMP type
For example, consider the following three object groups:
*MyServices - Includes the TCP and UDP port numbers of the service requests that are allowed access to the internal network.
*TrustedHosts - Includes the host and network addresses allowed access to the greatest range of services and servers.
*PublicServers - Includes the host addresses of servers to which the greatest access is provided.
After creating these groups, you could use a single ACE to allow trusted hosts to make specific service requests to a group of public servers.
You can also nest object groups in other object groups.

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