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NEW QUESTION: 1
A user, Ann, has been issued a smart card and is having problems opening old encrypted email. Ann published her certificates to the local windows store and to the global address list. Which of the following would still need to be performed?
A. Recover her old private certificate
B. Setup the email security with her new certificates
C. Verify the correct email address is associated with her certificate
D. Reinstall her previous public certificate
Answer: B

NEW QUESTION: 2
カスタムリストビューを作成するときに、そのオブジェクトのページレイアウトにないフィールドを表示できますか？
A. 本当
B. 偽
Answer: B

NEW QUESTION: 3
CORRECT TEXT
Problem Scenario 58 : You have been given below code snippet.
val a = sc.parallelize(List("dog", "tiger", "lion", "cat", "spider", "eagle"), 2) val b = a.keyBy(_.length) operation1
Write a correct code snippet for operationl which will produce desired output, shown below.
Array[(lnt, Seq[String])] = Array((4,ArrayBuffer(lion)), (6,ArrayBuffer(spider)),
(3,ArrayBuffer(dog, cat)), (5,ArrayBuffer(tiger, eagle}}}
Answer:
Explanation:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
b.groupByKey.collect
groupByKey [Pair]
Very similar to groupBy, but instead of supplying a function, the key-component of each pair will automatically be presented to the partitioner.
Listing Variants
def groupByKeyQ: RDD[(K, lterable[V]}]
def groupByKey(numPartittons: Int): RDD[(K, lterable[V] )]
def groupByKey(partitioner: Partitioner): RDD[(K, lterable[V])]