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  • Exam Code: C-THR85-2305
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Succession Management 1H/2023
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C-THR85-2305
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Succession Management 1H/2023
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C-THR85-2305
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Succession Management 1H/2023
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  • Q & A: 400 Questions and Answers
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NEW QUESTION: 1
展示を参照してください。

放射パターンはどのタイプのアンテナに存在しますか?
A. Patch
B. Yagi
C. Omnidirectional
D. Dipole
Answer: A

NEW QUESTION: 2
CORRECT TEXT

Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32.
Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 3

A. WSUS
B. SNMP
C. Remote management cards
D. Terminal services
E. Group policy
Answer: A,E

NEW QUESTION: 4
Examine this PeopleCode snippet:
&Date = ORDER.DATE;
Select the object-oriented equivalent.
A. &Date = GetValue(ORDER.DATE);
B. &Field = GetField(ORDER.DATE);&Date = &Field.Value;
C. &Field.Value = GetField(ORDER.DATE);
D. &Field = CreateField();&Date = &Field(ORDER.DATE);
E. &Date.GetValue = ORDER.DATE;
Answer: B

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