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NEW QUESTION: 1
Which iOS backup file will contain the last time the device was backed up?
A. manifest.mbdb
B. notes.sqlite
C. status.plist
D. info.plist
Answer: D
Explanation:
Explanation/Reference:
Explanation: The file info.plist contains many artifacts regarding the device, including the last time it was backed up. The file manifest.mbdb contains a list of data stored in the backup. The file status.plist contains details about the backup including a flag to identify the backup type, date and version. The file notes.sqlite is an android file that contains notes written by the user on the device.

NEW QUESTION: 2
大企業の多額の資金がなければ、中小企業はクラウド環境に移行することにより、次のどの概念に対してかなりの費用効果の高いサービスを得ることができますか？
A. セキュリティ
B. テスト
C. 規制
D. 開発
Answer: A
Explanation:
Cloud environments, regardless of the specific deployment model used, have extensive and robust security controls in place, especially in regard to physical and infrastructure security. A small company can leverage the extensive security controls and monitoring provided by a cloud provider, which they would unlikely ever be able to afford on their own. Moving to a cloud would not result in any gains for development and testing because these areas require the same rigor regardless of where deployment and hosting occur. Regulatory compliance in a cloud would not be a gain for an organization because it would likely result in additional oversight and auditing as well as require the organization to adapt to a new environment.

NEW QUESTION: 3
共有ライブラリを使用する必要があるアプリケーションには、共有ライブラリの仕様バージョンと拡張名のみを指定するデプロイメント記述子があります。アプリケーションがデプロイされると、どの共有ライブラリが使用されますか？
A. WebLogic管理コンソールを使用している場合は、使用するバージョンの入力を求められます。そうしないと、アプリケーションのデプロイに失敗します。
B. アプリケーションはデプロイされますが、共有ライブラリのクラスは使用できません。
C. デプロイされた共有ライブラリのバージョンが複数ある場合、WebLogicは最後にデプロイされたものを使用します。
D. 実装バージョンが必要なため、アプリケーションはADMIN状態になり、デプロイに失敗します。
E. デプロイされた共有ライブラリのバージョンが複数ある場合、WebLogicは実装バージョンが最も高いバージョンを使用します。
Answer: E
Explanation:
An internal application may be configured to always use a minimum version of the same library. Applications that require no specific version can be configured to use the latest version of the library.
Note:
* Specification-Version (a manifest Attributes for Java EE Libraries) An optional String value that defines the specification version of the shared Java EE library. Referencing applications can optionally specify a required Specification-Version for a library; if the exact specification version is not available, deployment of the referencing application fails. The Specification-Version uses the following format:
Major/minor version format, with version and revision numbers separated by periods (such as "9.0.1.1")
Referencing applications can be configured to require either an exact version of the shared Java EE library, a minimum version, or the latest available version.
*Implementation-Version (a manifest Attributes for Java EE Libraries)
An optional String value that defines the code implementation version of the shared
Java EE library. You can provide an Implementation-Version only if you have
also defined a Specification-Version.
*Extension-Name (a manifest Attributes for Java EE Libraries)
An optional string value that identifies the name of the shared Java EE library. Referencing
applications must use the exact Extension-Name value to use the library.
As a best practice, always specify an Extension-Name value for each library. If you do not specify an extension name, one is derived from the deployment name of the library. Default deployment names are different for archive and exploded archive deployments, and they can be set to arbitrary values in the deployment command.
*After a library is deployed, the extension-name, specification-version and implementation-version of the library can be found in Administration console.
Reference: Creating Shared Java EE Libraries and Optional Packages

NEW QUESTION: 4
Refer to the exhibit.

A new subnet with 60 hosts has been added to the network. Which subnet address should this network use to provide enough usable addresses while wasting the fewest addresses?
A. 192.168.1.64/26
B. 192.168.1.56/27
C. 192.168.1.56/26
D. 192.168.1.64/27
Answer: A
Explanation:
A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62
6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet.
8bits+ 8bits+ 8bits + 2bits = /26
/26 bits subnet is 24bits + 11000000 = 24bits + 192
256 - 192 = 64
0 -63
64 - 127