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NEW QUESTION: 1
HOTSPOT
You are developing an airline reservation website by using HTML5 and JavaScript. A page on the site allows users to enter departure and destination airport information and search for tickets.
You have the following requirements:
* Users must be able to save information in the application about their favorite destination airport.
* The airport information must be displayed in the destination text box whenever the user returns to the page.
You need to develop the site to meet the requirements.
Which lines of code should you use? (To answer, select the appropriate options from the drop-down lists in the answer area.)


A. sessionStorage.destination = dest;
B. var dest = localStorage.destination;
C. localStorage.destination = dest;
D. var dest = sessionStorage.destination;
Answer: B,C

NEW QUESTION: 2
You have implemented mutual route redistribution between OSPF and EIGRP on a border router. When checking the routing table on one of the OSPF routers within the OSPF routing domain, you are seeing some, but not all of the expected routes. Which two things should you verify to troubleshoot this problem?
(Choose two.)
A. The subnet keyword on the border router in the redistribute EIGRP command.
B. The missing EIGRP routes are present in the routing table of the border router.
C. The border router is using a proper seed metric for OSPF.
D. The border router is using a proper seed metric for EIGRP.
E. The administrative distance is set for OSPF and EIGRP.
Answer: A,B
Explanation:
Explanation/Reference:
Explanation:
We are checking the routing table on EIGRP routers not OSPF so we don't need to check the seed metric for OSPF. Besides OSPF doesn't need to specify seed metric as all external routes get a default metric of
20 (except for BGP, which is 1) -> A is not correct.
We must specify seed metrics when redistributing into EIGRP (and RIP). If not all the redistributed routes will not be seen but the question says only some routes are missing -> B is not correct.
The default administrative distance for external routes redistributed into EIGRP is 170 so we don't need to set it -> C is not correct.
We should check the routing table of the border router to see the missing OSPF routes are there or not. An incorrect distribute-list can block some routes and we can't see it in other EIGRP routers -> D is correct.
--------------------------------------------------------
Answer D is obvious that we should check all the routes we want to redistribute are present in the routing table of the border router. Let's discuss about answer E.
A rule of thumb when redistributing into OSPF is we should always include the "subnets" keyword after the redistributed route. For example:
router ospf 1
redistribute eigrp 100 subnets
This keyword makes sure all of the routes, including subnets are redistributed correctly into OSPF. For example these routes are learned via EIGRP:
+ 192.168.1.0/24
+ 192.168.2.0/25
+ 192.168.3.0/26
Then without the keyword "subnets", only 192.168.1.0/24 network is redistributed into OSPF.

NEW QUESTION: 3
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
D. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO, ELEMENTS
G. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
H. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO, ELEMENTS
Answer: H

NEW QUESTION: 4



A. Option D
B. Option E
C. Option C
D. Option B
E. Option A
Answer: B