Cisco 200-901 dumps - in .pdf

200-901 pdf
  • Exam Code: 200-901
  • Exam Name: DevNet Associate Exam
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: 200-901
  • Exam Name: DevNet Associate Exam
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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Cisco 200-901 dumps - Testing Engine

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  • Exam Code: 200-901
  • Exam Name: DevNet Associate Exam
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
  • Testing Engine

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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have only loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
Answer: C
Explanation:
Explanation
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp

NEW QUESTION: 2
Your network management system (NMS) reports memory consumption on a server to be
95%. You connect to the server and see a memory consumption of 80%.
What is a possible cause for this inconsistency?
A. WMI has been misconfigured on the server.
B. The NMS is displaying an average, whereas the server is displaying real-time data.
C. The NMS is using the wrong version of SNMP to poll the server.
D. The NMS is displaying real-time data, whereas the server is displaying an average.
Answer: B

NEW QUESTION: 3
What are three advantages of NAS? (Choose three.)
A. Easy to implement using the same protocols as file servers
B. Provides a high-speed data path between servers and storage
C. Clients running different operating systems can share the same files
D. File services can be extended to hundreds of devices
Answer: A,C,D

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