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  • Exam Code: CIMAPRA19-F03-1
  • Exam Name: F3 Financial Strategy
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: CIMAPRA19-F03-1
  • Exam Name: F3 Financial Strategy
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: CIMAPRA19-F03-1
  • Exam Name: F3 Financial Strategy
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have only loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
Answer: A
Explanation:
Explanation
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp

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Your network management system (NMS) reports memory consumption on a server to be
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C. The NMS is using the wrong version of SNMP to poll the server.
D. WMI has been misconfigured on the server.
Answer: B

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C. Clients running different operating systems can share the same files
D. File services can be extended to hundreds of devices
Answer: B,C,D

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