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NEW QUESTION: 1
DRAG DROP
You are a network administrator for a company named Humongous Insurance. Humongous Insurance has an Active Directory forest that contains two domains.
You install the Active Directory Rights Management Services server role on a server named ADRMS1. The Active Directory Rights Management Services (AD RMS) server uses an internal certification authority (CA) for all certificates.
You plan to provide users with the ability to use AD RMS to protect all of the email messages sent to a partner company named Contoso, Ltd.
Contoso does not have AD RMS deployed.
You need to identify which components from the Humongous Insurance network must be accessible to Contoso to ensure that the users at Contoso can open protected messages.
Which two components should you identify? (Each correct answer presents part of the solution. Choose two.)
A. the certificate revocation list (CRL)
B. the Active Directory domain controllers
C. the AD RMS cluster
D. the Client Access servers
E. the Mailbox servers
F. the Global Catalog servers
Answer: A,C

NEW QUESTION: 2
イーサネット接続とファイバーチャネル接続の両方について顧客の要件があるソリューションを検証しています。
ケーブルとアダプターをサポートされるテクノロジーに合わせます。

Answer:
Explanation:

NEW QUESTION: 3
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 8 kHz x 8-bit code words
C. 2 x 4 kHz x 8-bit code words
D. 2 x 4-bit code words x 8 kHz
Answer: C
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original perfectly from the sampled version."

NEW QUESTION: 4
A Sales force object can exist independent of an application.
A. False
B. True
Answer: B
Explanation:
Explanation/Reference: You do not have to create a custom tab or assign a custom object to an application.