Oracle 1z1-076 dumps - in .pdf

1z1-076 pdf
  • Exam Code: 1z1-076
  • Exam Name: Oracle Database 19c: Data Guard Administration
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: 1z1-076
  • Exam Name: Oracle Database 19c: Data Guard Administration
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Version + PC Test Engine + Online Test Engine
  • Value Pack Total: $103.96  $66.98
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  • Exam Code: 1z1-076
  • Exam Name: Oracle Database 19c: Data Guard Administration
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
  • Testing Engine

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NEW QUESTION: 1
Which of the following regarding per-platform label space is TRUE?
A. A separate label is used for each interface on which the FEC is advertised.
B. It uses more label resources than a per-interface label space.
C. A single label is assigned to a FEC for all interfaces on the same router,
D. It is typically used when the device has ATM or Frame Relay interfaces.
Answer: C

NEW QUESTION: 2
What is the most common way a computer can become infected with a bot?
A. Users accessing malicious web sites
B. Adobe file vulnerabilities
C. Microsoft file vulnerabilities
D. Malvertising
Answer: A

NEW QUESTION: 3
Concerning shared Ethernet, which of the following are true( )
A. It can implement full duplex flow control
B. It uses CSMA/CD media access mechanism
C. It needs collision detection
D. It can only implement half-duplex flow control
Answer: B,C,D

NEW QUESTION: 4
Refer to the exhibit.

A new subnet with 60 hosts has been added to the network. Which subnet address should this network use to provide enough usable addresses while wasting the fewest addresses?
A. 192.168.1.56/26
B. 192.168.1.64/26
C. 192.168.1.64/27
D. 192.168.1.56/27
Answer: B
Explanation:
A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62
6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet.
8bits+ 8bits+ 8bits + 2bits = /26
/26 bits subnet is 24bits + 11000000 = 24bits + 192
256 - 192 = 64
0 -63
64 - 127

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