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C_C4H225_12 pdf
  • Exam Code: C_C4H225_12
  • Exam Name: Certified Technology Associate - SAP Emarsys Customer Engagement Implementation
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C_C4H225_12
  • Exam Name: Certified Technology Associate - SAP Emarsys Customer Engagement Implementation
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C_C4H225_12
  • Exam Name: Certified Technology Associate - SAP Emarsys Customer Engagement Implementation
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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NEW QUESTION: 1
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
D. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: A
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx

NEW QUESTION: 2
A WebSphere MQ application has been designed to use triggering with TRIGTYPE(FIRST). Which of the following is recommended for the program that has been started to process the triggered queue?
A. Do not allow the program to end unless it MQGETs at least one message.
B. Do MQGET without the wait option so that the application program does not keep the queueopen unnecessarily.
C. Do MQGET with the wait option because the trigger message can be put, causing theapplication program to start, before all messages to be processed have been committed.
D. MQGET only the number of messages the program is expected to process, so additionalcopies of the program will be triggered to process subsequent messages.
Answer: C

NEW QUESTION: 3
Was sollte ein Informationssicherheitsmanager ZUERST tun, wenn er auf eine neue Regelung aufmerksam gemacht wird, die möglicherweise die Neugestaltung bestehender Informationssicherheitsprozesse erfordert?
A. Entwickeln Sie eine zukünftige staatliche Roadmap.
B. Führen Sie eine Kosten-Nutzen-Analyse durch.
C. Entwickeln Sie einen Business Case.
D. Führen Sie eine Lückenanalyse durch.
Answer: D

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