SAP C-GRCAC-13 dumps - in .pdf

C-GRCAC-13 pdf
  • Exam Code: C-GRCAC-13
  • Exam Name: Certified Application Associate - SAP Access Control 12.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: C-GRCAC-13
  • Exam Name: Certified Application Associate - SAP Access Control 12.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C-GRCAC-13
  • Exam Name: Certified Application Associate - SAP Access Control 12.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
  • Testing Engine

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NEW QUESTION: 1
Which functionalities does XCS provide? (Select four.)
A. support for dual controller interconnect
B. Data Protector Integration
C. support for maximum 512 Vdisks
D. support for direct connect for Windows
E. greater than 35 TB presentable capacity
F. support for dual mirror ports
Answer: A,D,E,F

NEW QUESTION: 2
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val>v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
B t2[]={5,6,8,2,1};
vector<B> v1(10,0);
sort(t1, t1+5);
sort(t2, t2+5);
set_intersection(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 1 2 3 4 5 6 8 2 1 0
B. 5 2 1 0 0 0 0 0 0 0
C. 1 2 5 0 0 0 0 0 0 0
D. 1 2 3 4 5 6 8 0 0 0
E. compilation error
Answer: B

NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten nur für diese Frage.
Sie haben eine Microsoft SQL Server-Datenbank mit dem Namen DB1, die die in der folgenden Tabelle beschriebenen Tabellen enthält:

Es gibt keine Fremdschlüsselbeziehungen zwischen TBL1 und TBL2.
Sie müssen den Zeitaufwand für Abfragen, die Daten aus TBL1 und TBL2 für die Rückgabe von Daten verwenden, minimieren.
Was tun?
A. Erstellen Sie eindeutige Einschränkungen für TBL1 und TBL2. Erstellen Sie eine partitionierte Ansicht, die Spalten aus TBL1 und TBL2 kombiniert.
B. Erstellen Sie Clustered-Indizes für TBL1 und TBL2.
C. Erstellen Sie einen nicht gruppierten Index nur für tbl2.
D. Erstellen Sie einen Clustered-Index für TBL1. Erstellen Sie einen Nonclustered-Index für TBL2 und fügen Sie die am häufigsten abgefragten Spalten als eingeschlossene Spalten hinzu.
E. Löschen Sie vorhandene Indizes in TBL1 und erstellen Sie dann einen Clustered-Columnstore-Index. Erstellen Sie einen nicht gruppierten Columnstore-Index für TBL1. Erstellen Sie einen Noncluster-Index für TBL2.
F. Löschen Sie vorhandene Indizes in TBL1 und erstellen Sie dann einen Clustered-Columnstore-Index. Erstellen Sie einen nicht gruppierten Columnstore-Index für TBL1. Nehmen Sie keine Änderungen an TBL2 vor.
Answer: D

NEW QUESTION: 4
クリティカルパスでのタスクの見積もりが正しくないため、プロジェクトが予定より遅れています。プロジェクトマネージャーは何をすべきですか?
A. 問題をお客様に説明し、どの程度の遅延が予想されるかを正確にアドバイスします。
B. チームメンバーに、タスクが誤って見積もられた理由を顧客に説明するように依頼します
C. コミットされたタイムラインを超えたときに顧客に通知し、回避策を計画します。
D. 顧客に通知する前に、高速追跡またはクラッシュ技術がスケジュールを軌道に乗せるかどうかを分析します
Answer: A

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