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NEW QUESTION: 1
A security team is auditing a company's network logs and notices that a USB drive was previously inserted into several of the servers. Many login attempts were than successfully performed using common login information. Which of the following actions should be taken to close the vulnerability? (Select two.)
A. Run OS security updates
B. Change default credentials
C. Disable guest account
D. Install a software firewall
E. Remove admin permissions
F. Modify AutoRun settings
Answer: B,C

NEW QUESTION: 2
CORRECT TEXT

Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can
find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111
1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the
formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment
= 25 = 32. Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the
previous IP - 209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27
Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address
of this subnet)
Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful)
Apopka(config-if)#ip address 192.0.2.142 255.255.255.240
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 3
コンパイルされたJavaソースファイルからコードスニペットを指定すると：

次の出力を得るために、どのコマンドライン引数をプログラムに渡すべきですか？ Argは2です
A. java MyFile 1 2 2 3 4
B. java MyFile 1 3 2 2
C. java MyFile 0 1 2 3
D. java MyFile 2 2 2
Answer: B