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NEW QUESTION: 1
次のサービスのうち、必要に応じてストレージを自動的に拡張するMySQL互換データベースはどれですか。
A. アマゾンオーロラ
B. Amazon Elastic Compute Cloud（Amazon EC2）
C. MySQL用のAmazon Relational Database Service（Amazon RDS）
D. Amazon Lightsail
Answer: A
Explanation:
Explanation
Amazon Aurora is a relational database service that combines the speed and availability of high-end commercial databases with the simplicity and cost-effectiveness of open source databases. The MySQL-compatible edition of Aurora delivers up to 5X the throughput of standard MySQL running on the same hardware, and enables existing MySQL applications and tools to run without requiring modification.
Amazon Aurora will automatically grow the size of your database volume as your database storage needs grow. Your volume will grow in increments of 10 GB up to a maximum of 64 TB. You don't need to provision excess storage for your database to handle future growth.
Reference: https://aws.amazon.com/rds/aurora/mysql-features/

NEW QUESTION: 2
Refer to the exhibit.
86 / 162
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IP phone 1 has MAC address of 1111.1111.1111, and IP phone 2 has MAC address of 2222.2222.2222.
The first two incoming calls were answered by IP phone 1, and the third incoming call was answered by IP phone 2.
Which option describes what will happen to the fourth incoming call?
A. Both phones ring and either phone can answer the call.
B. Both phones ring, but only IP phone 1 can answer the call.
C. Neither phone rings and the call is forwarded to 2100.
D. Both phones ring, but only IP phone 2 can answer the call.
E. Neither phone rings and the call is forwarded to 2200.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
IP Phone 1 & 2 both has busy-trigger-per-button configured to 3 & 2 resectively.So,the 4thincoming call will get forwarded to 2100 as busy-triggers are exceed in IP Phones. Explanation:
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucme/command/reference/cme_cr/cme_c1 ht.html#wp1570384096

NEW QUESTION: 3
View the exhibit and examine the structure of the EMPLOYEES table.

You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id and AND e.manager_id = 100
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id = 100;
Answer: B