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NEW QUESTION: 1

A. FE81::280f:512b:e14f:3d69
B. FE08::280e:611:a:f14f:3d69
C. FEFE:0345:5f1b::e14d:3d69
D. FE80::380e:611a:e14f:3d69
Answer: D
Explanation:
Understanding IPv6 Link Local Address Reference:
http://www.cisco.com/en/US/tech/tk872/technologies_configuration_example09186a0080b a1d07.shtml
The purpose of this document is to provide an understanding of IPv6 Link-local address in a network. A linklocal address is an IPv6 unicast address that can be automatically configured on any interface using the linklocal prefix FE80::/10 (1111 1110 10) and the interface identifier in the modified EUI-64 format. Link-local addresses are not necessarily bound to the MAC address (configured in a EUI-64 format). Link-local addresses can also be manually configured in the FE80::/10 format using the ipv6 address link-local command.

NEW QUESTION: 2
What method is recommended for mapping out an organization's current processes and to design future processes?
A. Writing detailed descriptions
B. Querying relational databases
C. Drawing a business model diagram
D. Drawing hierarchical matrixes
Answer: C

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
struct Add {
B operator()(B & a, B & b) { return a+b; }};
int main() {
int t[]={1,2,3,4,5,6,7,8,9,10};
vector<B> v1(t, t+10);
vector<B> v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(1,Add()));
for_each(v2.rbegin(), v2.rend(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 1 2 3 4 5 6 7 8 9 10
B. 11 10 9 8 7 6 5 4 3 2
C. compilation error
D. 2 3 4 5 6 7 8 9 10 11
E. 10 9 8 7 6 5 4 3 2 1
Answer: C