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  • Exam Code: C_THR81_2311
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Employee Central Core 2H/2023
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C_THR81_2311
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Employee Central Core 2H/2023
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C_THR81_2311
  • Exam Name: SAP Certified Application Associate - SAP SuccessFactors Employee Central Core 2H/2023
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
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NEW QUESTION: 1
You have a server named Server1 that runs Windows Server 2016. Server1 has four SCSI disks and a storage pool named Pool1 that contains three disks.
You create a virtual disk named Disk 1 that uses a mirrored layout.
You create a partition named Partition1 that uses all of the available space on Disk 1.
You need to extend Partition1.
What should you do first?
A. From the Storage Pools page in Server Manager, extend a virtual disk.
B. From Windows PowerShell, run the Resize-StorageTier cmdlet.
C. From Disk Management, extend a volume.
D. From Windows PowerShell, run the Resize-Partition cmdlet.
E. From Disk Management, modify the properties of Partition1.
Answer: A
Explanation:
Explanation/Reference:
References: https://charbelnemnom.com/2015/03/step-by-step-how-to-extend-and-resize-a-two-way- mirrored-storage-tiered-space-storagespaces-ws2012r2/

NEW QUESTION: 2
Which of the following are characteristics of SIP? (Choose three)
A. It supports multimedia applications for new business process applications.
B. It supports only point-to-point connections.
C. It enables voice and multimedia services such as voice enriched eCommerce, Web page click-to-dial, and instant messaging with buddy lists.
D. It operates at the network layer.
Answer: A,B,C

NEW QUESTION: 3
Refer to the exhibit. How will the redistributed routes on R1 from EIGRP into OSPF be installed in the R4 routing table?

A. as specific routes with an E2 route type
B. as a default route with an N2 route type
C. as a default route with an IA route type
D. as a default route with an E2 route type
E. as specific routes with an N2 route type
Answer: C
Explanation:
Explanation/Reference:
http://www.cisco.com/c/en/us/support/docs/ip/open-shortest-path-first-ospf/6208-nssa.html
http://www.cisco.com/image/gif/paws/6208/nssa.pdf

NEW QUESTION: 4
Which of the following is NOT a key recovery method?
A. A secret key or a private key is broken into a number of parts and
each part is deposited with a trustee agent. The agents can then
provide their parts of the key to a central authority, when presented
with appropriate authorization. The key can then be reconstructed
and used to decrypt messages encrypted with that key.
B. A message is encrypted with a session key and the session key is, in turn, encrypted with the private key of a trustee agent. The encrypted session key is sent along with the encrypted message. The
trustee, when authorized, can then decrypt the message by
recovering the session key with the trustee's public key.
C. A message is encrypted with a session key. The session key, in turn, is broken into parts and each part is encrypted with the public key of a different trustee agent. The encrypted parts of the session key
are sent along with the encrypted message. The trustees, when
authorized, can then decrypt their portion of the session key and
provide their respective parts of the session key to a central agent.
The central agent can then decrypt the message by reconstructing
the session key from the individual components.
D. A message is encrypted with a session key and the session key is, in turn, encrypted with the public key of a trustee agent. The encrypted session key is sent along with the encrypted message. The
trustee, when authorized, can then decrypt the message by recovering
the session key with the trustee's private key.
Answer: B
Explanation:
Encrypting parts of the session key with the private keys of the
trustee agents provides no security for the message since the
message can be decrypted by recovering the key components of
the session key using the public keys of the respective agents. These
public keys are available to anyone.
The other answers are valid means of recovering keys, since key recovery refers to permitting access to encrypted messages under predefined circumstances.
Two of these answers are also called key encapsulation since the session key is encapsulated in the public keys of the trustee agents and, therefore, can be decrypted only by these trustee agents with their
private keys.

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