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NEW QUESTION: 1
A significant difference between independent estimates and proposed pricing could mean that:
A. The prospective seller either misunderstood or failed to respond fully to the SOW.
B. The SOW was not adequate
C. The independent estimates are most likely incorrect and the proposed pricing correct
D. b or c
E. a or c
Answer: D

NEW QUESTION: 2
What is a bundle?
A. a container for one or more packages
B. a set of resources that makes up a package
C. a set of raw log events before they are parsed
D. a data transmission containing SSL information
Answer: A

NEW QUESTION: 3
Die Wirksamkeit von Sicherheitsbewusstseinsprogrammen bei der Förderung positiver Sicherheitskulturen hängt am meisten von den Mitarbeitern ab:
A. Kenntnis der regulatorischen Anforderungen.
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C. Fähigkeit zur Durchführung sicherheitsrelevanter Verfahren.
D. Verständnis der Strafen für Nichteinhaltung.
Answer: B

NEW QUESTION: 4
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 2 x 4-bit code words x 8 kHz
C. 8 kHz x 8-bit code words
D. 2 x 4 kHz x 8-bit code words
Answer: D
Explanation:
Explanation/Reference:
Explanation: While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses
sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and
sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency
sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz.
According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the
unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per
second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must
be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original
perfectly from the sampled version."