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NEW QUESTION: 1
質問をドラッグアンドドロップ
説明を左から右の正しいQoSコンポーネントにドラッグアンドドロップします。

Answer:
Explanation:

Explanation:
次の図は、トラフィックポリシングとトラフィックシェーピングの主な違いを示しています。
トラフィックポリシングはバーストを伝播します。トラフィックレートが設定された最大レート（または認定情報レート）に達すると、過剰なトラフィックがドロップ（または再マーキング）されます。結果は、山と谷を持つ鋸歯状に見える出力レートです。ポリシングとは対照的に、トラフィックシェーピングは過剰なパケットをキューに保持し、時間の増分で後で送信するために超過をスケジュールします。トラフィックシェーピングの結果は、平滑化されたパケット出力レートです。
注：認定情報レート（CIR）：ルーティングデバイスによって合意された最小保証データ転送レート。

NEW QUESTION: 2
Welche der folgenden Eigenschaften ermöglicht es einem 802.11g WAP, Übertragungsgeschwindigkeiten von bis zu zu erreichen
108 Mbit / s?
A. Verschlüsselungstyp
B. Kanalbindung
C. Frequenz
D. MIMO-Technologie
Answer: B

NEW QUESTION: 3
What will configuring the FCP service for a Vserver do?
A. It will log the storage controllers' target adapters into the attached Fibre Channel fabric.
B. It will create a target World Wide Node Name for the Vserver.
C. It will allow igroups to be created on the Vserver.
D. It will disable any NAS protocols for that Vserver.
Answer: B
Explanation:
Reference:https://library.netapp.com/ecmdocs/ECMP1196817/html/vserver/fcp/create.html

NEW QUESTION: 4
ネットワークエンジニアがOSPFv2ネイバー隣接関係を設定しています。パラメータを左側から右側の必要なカテゴリにドラッグアンドドロップしてください。すべてのパラメーターが使用されるわけではありません

Answer:
Explanation: