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NEW QUESTION: 1
What is the recommendation for the maximum number of APs per VLAN?
A. 20 to 40
B. 80 to 100
C. 60 to 80
D. 100 to 120
E. 40 to 60
Answer: C

NEW QUESTION: 2
Which option is one essential characteristic of Cloud computing?
A. It must provide on-demand self service.
B. It must use virtualization.
C. It must provide load balancing services.
D. It must run on open source software.
Answer: A
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
C. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H