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NEW QUESTION: 1
What is the effect of using the service password-encryption command?
A. It will encrypt the secret password and remove the enable secret password from the configuration.
B. Only passwords configured after the command has been entered will be encrypted.
C. Only the enable password will be encrypted.
D. It will encrypt all current and future passwords.
E. Only the enable secret password will be encrypted.
Answer: D
Explanation:
Enable vty, console, AUX passwords are configured on the Cisco device. Use the show run command to show most
passwords in clear text. If the service password-encryption is used, all the passwords are encrypted. As a result, the
security of device access is improved.

NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
E. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROMtblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
Answer: F
Explanation:
Explanation
Would list the customers with duplicates, which would equal the number of accounts.

NEW QUESTION: 3
Refer to Exhibit:

If an administrator changes the Archive Naming Convention setting, the administrator must also perform two additional steps to ensure the policy functions correctly. Which two steps are required? (Select two.)
A. ensure that "Allow script in shared folders" is set to Force On in the Desktop policy
B. synchronize mailboxes
C. ensure that inherited permissions is turned On in the Mailbox policy
D. ensure that "Reset archive names" is On in the Mailbox policy
E. ensure that "Warn if default or anonymous permissions exist" setting is On in the Mailbox policy
Answer: B,D