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NEW QUESTION: 1
Out of a box that contains 4 black mice and 6 white ones, three are picked up. What is the probability that all three will be black mice?
A. 8/125.
B. 3/10.
C. 1/30.
D. 2/5.
E. 1/720.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The probability for the first one to be black is: 4/(4+6) = 2/5.
The probability for the second one to be black is: 3/(3+6) = 1/3.
The probability for the third one to be black is: 2/(2+6) = 1/4.
The probability for all three events is (2/5) x (1/3) x (1/4) = 1/30.

NEW QUESTION: 2
Which statement describes the QoS behavior between P and PE routers of an MPLS provider network for an L3VPN service?
A. The PE function cannot map DSCP markings to MPLS EXP bits.
B. The customer and provider must agree on DSCP classification and traffic priorities.
C. Classification of customer traffic is handled by the P router.
D. The PE function honors DSCP markings set by the CE.
Answer: B

NEW QUESTION: 3
Given this portion of the network diagram to the right, what's the LF of activity F?
A. 0
B. 1
C. 2
D. 3
Answer: D
Explanation:
It's just easy to calculate the late finish (LF) of an activity in a network diagram. Look at the following activity, take its LS (late start), and subtract one. If there's more than one following activity, use the one with the lowest LS. So for activity F in the question, the following activities are G, with an LS of 17, and H, with an LS of 11. So the LF of F is 11 - 1 = 10.