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  • Exam Code: FCSS_ASA_AR-6.7
  • Exam Name: FCSS—Advanced Analytics 6.7 Architect
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: FCSS_ASA_AR-6.7
  • Exam Name: FCSS—Advanced Analytics 6.7 Architect
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: FCSS_ASA_AR-6.7
  • Exam Name: FCSS—Advanced Analytics 6.7 Architect
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
  • Testing Engine

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NEW QUESTION: 1
Oracle Cloud Infrastructure Budgets can be set on which two options?
A. Tenancy
B. Cost-tracking tags
C. Compartments
D. Free-form tags
E. Virtual Cloud Network
Answer: B,C
Explanation:
Budgets are set on cost-tracking tags or on compartments (including the root compartment) to track all spending in that cost-tracking tag or for that compartment and its children.
https://docs.cloud.oracle.com/en-us/iaas/Content/Billing/Concepts/budgetsoverview.htm

NEW QUESTION: 2
You can use cloud scheduler to send meeting invites to contacts or leads or person accounts you don't have visibility to.
A. False
B. True
Answer: A

NEW QUESTION: 3
Solutions Architect는 Amazon ECS를 사용하여 마이크로 서비스 기반 애플리케이션을 설계하고 있습니다. 응용 프로그램에는 WebSocket 구성 요소가 포함되며 트래픽은 URL을 기반으로 마이크로 서비스간에 분산되어야 합니다.
Architect는 어떤 서비스를 선택하여 워크로드를 분배해야 합니까?
A. ELB 클래식로드 밸런서
B. Amazon CloudFront
C. Amazon Route 53 DNS
D. ELB 애플리케이션로드 밸런서
Answer: D

NEW QUESTION: 4



A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: B

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