CLA-11-03 Lernhilfe & CLA-11-03 Vorbereitungsfragen - CLA-11-03 Prüfungs-Guide - Championlandzone

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  • Vendor : C++ Institute
  • Certifications : C++ Institute Certification
  • Exam Name : CLA - C Certified Associate Programmer
  • Exam Code : CLA-11-03
  • Total Questions : 376 Q&As
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VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.
SKU: CLA-11-03 Categories: ,

Description

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Typically, IPv4 address space is assigned to end users by ISPs or NIRs.Transition to IPv6 will involve changes to the supporting systems and infrastructure on a global scale.Note IPv6 support in the OpenDNS Sandbox is limited to standard C++ Institute CLA-11-03 recursive DNS initially.

Note IPv6 support in the OpenDNS Sandbox is limited to standard recursive DNS initially.Most CLA - C Certified Associate Programmer operating systems including mobile phones and most network devices support IPv6, but some equipment and applications may not.

Most operating systems including mobile phones and most network devices support IPv6, but some equipment and applications may not.If there s no way to run a third party service locally you should opt CLA - C Certified Associate Programmer CLA-11-03 for running a dedicated test instance and point at this test instance when running your integration tests.

If there s no way to run a third party service locally you should opt for running a dedicated test instance and point at this test instance when running your integration tests.


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    NEW QUESTION: 1
    You have a SnapVault backup from your primary site to your secondary site with a LUN in the volume.
    In this scenario, what is transferred?
    A. serial number
    B. selected Snapshot copies
    C. LUN mapping status
    D. UUID
    Answer: B

    NEW QUESTION: 2
    A bond with a 5% coupon trades at 95. An increase in interest rates by 10 bps causes its price to decline to
    $94.50. A decrease in interest rates by 10 bps causes its price to increase to $95.60. Estimate the modified duration of the bond.
    A. 0
    B. 1
    C. 5.5
    D. 5.79
    Answer: D
    Explanation:
    Explanation
    In this case, we can estimate the duration of the bond as follows: we know that a 10 bps increase in rates causes the price to move to $94.50, and a 10 bps decrease causes the price to increase to $95.60. Thus, over the range of the 20 bps, the average change in price per basis point is ($95.60 - $94.50)/20 bps = $1.10/20 =
    $0.055/basis point, or $0.055* 100 = $5.5 for 100 basis points (ie 1%). We know that modified duration is equivalent to the percentage change in the bond price as a result of a 1% change in interest rates. A 1% change in the interest rates leading to a $5.5 change in a bond priced at $95 equates to $5.5/$95 = 5.79%, in other words the modified duration is roughly equal to 5.79 years.
    In fact if we know the price of a bond at any two different interest rates, we can make an estimate of modified duration. Modified duration is just the first derivative with respect to price, and given two prices and the associated yields, we can easily calculate modified duration to be the ratio of the change in price to the change in interest rates. In this question, we are given both an up move and a down move. Using this estimation, only one data point (ie, either the up price or the down price) in addition to the starting point ($95) would have been enough to come to a rough estimate of modified duration. You will notice that the modified duration would be slightly different if we were to use the high point and the starting point (ie $95.60 and $95), and the starting point and the lower point ($95 and $94.50). The difference is due to convexity. The decrease in price is lower than the increase in price - and this is due to the convexity of the bond.

    NEW QUESTION: 3
    Frank has a portlet that accesses PUMA to retrieve some details about a user to control what is displayed in his custom portlet (user categories). After some analysis, he sees that performance is poor and feels that this issue is because of PUMA. Frank would like to store some of the PUMA objects in the session.
    Which PUMA object can be stored safely in the session?
    A. PumaProfile
    B. PumaHome
    C. PumaController
    D. PumaLocator
    Answer: B
    Explanation:
    Explanation : PumaProfile Contains methods that provide read-only access to the User and Group attributes and identifiers. You can use this interface to get the User object for the current user. PumaLocator Contains methods for looking up User and Group objects. You can use this interface to obtain a List of Group objects for all of the groups in which the current user is a member. Beginning with Version 7.0 of WebSphere@ Portal, paging is supported. Which means that the result set is split up into subsets (pages) and a special iterator can be used to access the pages. PumaController Contains methods for creating and deleting Users and Groups and for modifying the User and Group profiles and membership. PumaEnvironment Contains methods to retrieve virtual principals, access general properties for user management, and a method to bypass access control for the user and group management layer. Before the portlet can use these provider objects, it must first retrieve the appropriate home interface, depending on the type of application.
    Standard portlet com.ibm.portal.um.portletservice.PumaHome


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