H11-879 Online Praxisprüfung & H11-879 Testantworten - H11-879 Zertifizierungsfragen - Championlandzone

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  • Vendor : Huawei
  • Certifications : HCIE-Enterprise Communication
  • Exam Name : HCIE-Enterprise Communication (Written) V1.0
  • Exam Code : H11-879
  • Total Questions : 376 Q&As
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VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.
SKU: H11-879 Categories: ,

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BT Mobile terms of service apply to all customers taking up any of these offers, and are available at legalstuff.Typically, IPv4 address space is assigned HCIE-Enterprise Communication H11-879 to end users by ISPs or NIRs.

Typically, IPv4 address space is assigned to end users by ISPs or NIRs.Transition to IPv6 will involve changes to the supporting systems and infrastructure on a global scale.Note IPv6 support in the OpenDNS Sandbox is limited to standard Huawei H11-879 recursive DNS initially.

Note IPv6 support in the OpenDNS Sandbox is limited to standard recursive DNS initially.Most HCIE-Enterprise Communication (Written) V1.0 operating systems including mobile phones and most network devices support IPv6, but some equipment and applications may not.

Most operating systems including mobile phones and most network devices support IPv6, but some equipment and applications may not.If there s no way to run a third party service locally you should opt HCIE-Enterprise Communication (Written) V1.0 H11-879 for running a dedicated test instance and point at this test instance when running your integration tests.

If there s no way to run a third party service locally you should opt for running a dedicated test instance and point at this test instance when running your integration tests.


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    NEW QUESTION: 1
    DRAG DROP


    Answer:
    Explanation:


    NEW QUESTION: 2
    Two wireless IP phones are never able to call each other when connected to the same autonomous AP. However, they can place calls to other wireless IP phones that are connected to other APs or to wired IP phones. The wireless phones are operating on VLAN 100.
    Based on this output, which statement about the problem is true?

    A. P2P blocking is enabled via the bridge-group 100 block-unknow-source command.
    B. P2P blocking is enabled via the no bridge-group 100 source-larning command.
    C. P2P blocking is enabled via the no bridge-group 100 unicast-flooding command.
    D. P2P blocking is enabled via the bridge-group 100 subscriber-loop-control command.
    E. P2P blocking is enabled via the bridge-group 100 port-protected command.
    Answer: E
    Explanation:
    Public Secure Packet Forwarding (PSPF) prevents client devices associated to an access point from inadvertently sharing files or communicating with other client devices associated to the access point. It provides Internet access to client devices without providing other capabilities of a LAN. This feature is useful for public wireless networks like those installed in airports or on college campuses.

    Note To prevent communication between clients associated to different access points, you must set up protected ports on the switch to which the wireless devices are connected. See the "Configuring Protected Ports" section for instructions on setting up protected ports.
    To enable and disable PSPF using CLI commands on the wireless device, you use bridge groups. You can find a detailed explanation of bridge groups and instructions for implementing them in this document:
    * Cisco IOS Bridging and IBM Networking Configuration Guide, Release 12.2. Click this link to browse to the Configuring Transparent Bridging chapter: http://www.cisco.com/univercd/cc/td/doc/product/software/ios122/122cgcr/fibm_c/bcfpart
    1/bcftb.htm
    You can also enable and disable PSPF using the web-browser interface. The PSPF setting is on the Radio Settings pages.
    PSPF is disabled by default. Beginning in privileged EXEC mode, follow these steps to enable PSPF:

    http://www.cisco.com/c/en/us/td/docs/wireless/access_point/12-
    3_8_JA/configuration/guide/1238jasc/s38rf.html#wp1038494

    NEW QUESTION: 3
    You administer an Azure Storage account named contosostorage. The account has a blob container to store image files. A user reports being unable to access an image file.
    You need to ensure that anonymous users can successfully read image files from the container.
    Which log entry should you use to verify access?

    A. Option C
    B. Option D
    C. Option A
    D. Option B
    Answer: C
    Explanation:
    Explanation/Reference:
    Explanation:
    Option A includes AnonymousSuccess.
    References: https://blogs.msdn.microsoft.com/windowsazurestorage/2011/08/02/windows-azure-storage- logging-using-logs-to-track-storage-requests/

    NEW QUESTION: 4
    Given the network diagram.

    Which address would successfully summarize only the networks seen?
    A. 192.168.16.0/21
    B. These networks cannot be summarized.
    C. 192.168.8.0/20
    D. 192.168.8.0/21
    E. 192.168.0.0/24
    F. 192.168.12.0/20
    Answer: D
    Explanation:
    let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary. In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21. if you make it in binary you'll find out the answer too: the interesting octet is 3rd one so let's convert in binary. 8 0000 1000 9 0000 1001 10 0000 1010 11 0000 1011 12 0000 1100 13 0000 1101 14 0000 1110 15 0000 1111 I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0


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